Sunday, October 17, 2010
Yesterday, (October 16, 2010) I watched the the Hawaii VS. Nevada football game. After watching the play replay of the Nevada player, Mike Ball, make a 84-yard kickoff return, I noticed that when the first diving tackle missed by a Hawaii player, the player slid about 2 meters before coming to a rest. This is due to friction. When the football player dove, he had an initial velocity and was like a projectile. However, after he hit the ground, he slid across the ground before stopping. After watching this, I decided to try and the find mu of his jersey to the AstroTurf. We can find the mu. Because he was sprinting before he dove, his initial velocity was around 7 m/s. If he slid 3 meters on the ground then we know his acceleration is- 8.2 m/s^2 because 7^2=2(a)3. If his weight was 200 pounds, then his normal force would also be around 200 pounds. 200 pounds is equal to about 890 newtons and this means his mass is 81.6 (890/9.8 = 81.6 kg). a=Net Force/ mass. Net Force = 81.6*-8.2=-670N. Friction = 670N. 890*mu = 670N and therefore mu is 0.75.
Monday, October 4, 2010
Blog 3
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